What is the integral from 2 to 5 of-3/(x^2) ?

The integral from 2 to 5 of-3/(x^2) is -9/10

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integral from 2 to 5 of-3/(x^2)

\int_{2}^{5} - \frac{3}{x ^{2}} d x

- \frac{9}{10}

Decimal

- 0.9

Solution steps

\int_{2}^{5} - \frac{3}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 3 \cdot \int_{2}^{5} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{5}

= - 3 [- \frac{1}{x}]_{2}^{5}

Compute the boundaries:

\frac{3}{10}

= - 3 \cdot \frac{3}{10}

Simplify

= - \frac{9}{10}

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What is the integral from 2 to 5 of-3/(x^2) ?
The integral from 2 to 5 of-3/(x^2) is -9/10