What is the integral from-pi/6 to pi/6 of cos(x) ?

The integral from-pi/6 to pi/6 of cos(x) is 1

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integral from-pi/6 to pi/6 of cos(x)

\int_{- \frac{π}{6}}^{\frac{π}{6}} cos (x) d x

1

Solution steps

\int_{- \frac{π}{6}}^{\frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{- \frac{π}{6}}^{\frac{π}{6}}

Compute the boundaries:

1

= 1

\int_{- π}^{π} \frac{x}{1 + cos ( x )} d x

\int_{- 1}^{1} (x + 1)^{5} d x

\int_{1}^{10} \frac{x}{x ^{2} + 4} d x

\int_{3}^{7} x 3 x + 1 d x

\int_{2}^{x} t ln (t) d t

What is the integral from-pi/6 to pi/6 of cos(x) ?
The integral from-pi/6 to pi/6 of cos(x) is 1