What is the integral from 1 to 8 of x^{-7/3} ?

The integral from 1 to 8 of x^{-7/3} is 45/64

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 8 of x^{-7/3}

\int_{1}^{8} x^{- \frac{7}{3}} d x

\frac{45}{64}

Decimal

0.703125

Solution steps

\int_{1}^{8} x^{- \frac{7}{3}} d x

Apply the Power Rule

: [- \frac{3}{4 x ^{\frac{4}{3}}}]_{1}^{8}

= [- \frac{3}{4 x ^{\frac{4}{3}}}]_{1}^{8}

Compute the boundaries:

\frac{45}{64}

= \frac{45}{64}

\int_{- \frac{π}{8}}^{\frac{π}{12}} cos (2 x) d x

\int_{0}^{6} (x^{2} - 4 x) d x

\int_{0}^{2} (x - 5) (x - 3) d x

\int_{1}^{e} 9 x^{2} ln (x) d x

\int_{0}^{1} 60 x (2 x^{2} + 1)^{4} d x

What is the integral from 1 to 8 of x^{-7/3} ?
The integral from 1 to 8 of x^{-7/3} is 45/64