What is the integral from 1 to 5 of (2/x) ?

The integral from 1 to 5 of (2/x) is 2ln(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of (2/x)

\int_{1}^{5} (\frac{2}{x}) d x

2 ln (5)

Decimal

3.21887 \dots

Solution steps

\int_{1}^{5} \frac{2}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{5} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= 2 [ln ∣ x ∣]_{1}^{5}

Compute the boundaries:

ln (5)

= 2 ln (5)

\int_{1}^{4} ln (4 x) d x

\int_{0}^{t} t e^{t} d t

\int_{0}^{1} 9 - x^{2} d x

\int_{0}^{2} x cos (π x) d x

\int_{0}^{26} x^{2} - 13 d x

What is the integral from 1 to 5 of (2/x) ?
The integral from 1 to 5 of (2/x) is 2ln(5)