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Popular >

integral from-1 to 2 of-y^2+y+2

Solution

\int_{- 1}^{2} - y^{2} + y + 2 d y

Solution

\frac{9}{2}

+1

Decimal

4.5

Solution steps

\int_{- 1}^{2} - y^{2} + y + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} y^{2} d y + \int_{- 1}^{2} y d y + \int_{- 1}^{2} 2 d y

\int_{- 1}^{2} y^{2} d y = 3

\int_{- 1}^{2} y d y = \frac{3}{2}

\int_{- 1}^{2} 2 d y = 6

= - 3 + \frac{3}{2} + 6

Simplify

- 3 + \frac{3}{2} + 6 : \frac{9}{2}

= \frac{9}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of-y^2+y+2 ?
The integral from-1 to 2 of-y^2+y+2 is 9/2