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Popular >

integral from 1 to 4 of t^2-t-6

Solution

\int_{1}^{4} t^{2} - t - 6 d t

Solution

- \frac{9}{2}

+1

Decimal

- 4.5

Solution steps

\int_{1}^{4} t^{2} - t - 6 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} t^{2} d t - \int_{1}^{4} t d t - \int_{1}^{4} 6 d t

\int_{1}^{4} t^{2} d t = 21

\int_{1}^{4} t d t = \frac{15}{2}

\int_{1}^{4} 6 d t = 18

= 21 - \frac{15}{2} - 18

Simplify

21 - \frac{15}{2} - 18 : - \frac{9}{2}

= - \frac{9}{2}

Graph

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\int_{0}^{2} 6 x^{3} x^{4} + 9 d x

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\int_{1}^{4} 5 - 2 x + 3 x^{2} d x

integral from 0 to 5 of 250000e^{-0.1x}

\int_{0}^{5} 250000 e^{- 0.1 x} d x

integral from-1 to 2 of (x^2-2x+2)

\int_{- 1}^{2} (x^{2} - 2 x + 2) d x

integral from 0 to 5 of (x^2+2x-15)

\int_{0}^{5} (x^{2} + 2 x - 15) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of t^2-t-6 ?
The integral from 1 to 4 of t^2-t-6 is -9/2