What is the integral from 0 to 5 of (x^3) ?

The integral from 0 to 5 of (x^3) is 625/4

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integral from 0 to 5 of (x^3)

\int_{0}^{5} (x^{3}) d x

\frac{625}{4}

Decimal

156.25

Solution steps

\int_{0}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{5}

= [\frac{x ^{4}}{4}]_{0}^{5}

Compute the boundaries:

\frac{625}{4}

= \frac{625}{4}

\int_{0}^{2} x (2 x - x^{2}) d x

\int_{0}^{π} - x cos (x) + x d x

\int_{1}^{e} 2 \frac{1}{x} d x

\int_{0}^{4} (- 2 x + 3) d x

\int_{0}^{3} (3 x + 2) (x - 5) d x

What is the integral from 0 to 5 of (x^3) ?
The integral from 0 to 5 of (x^3) is 625/4