What is the integral from pi/2 to 2pi of sin(x) ?

The integral from pi/2 to 2pi of sin(x) is -1

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integral from pi/2 to 2pi of sin(x)

\int_{\frac{π}{2}}^{2 π} sin (x) d x

- 1

Solution steps

\int_{\frac{π}{2}}^{2 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{\frac{π}{2}}^{2 π}

Compute the boundaries:

- 1

= - 1

\int_{0}^{4} x - x^{2} d x

\int_{- 1}^{1} (2 cos (\frac{π}{3} x)) d x

\int_{50}^{100} \frac{x}{14 + 3 x ^{2}} d x

\int_{- 2}^{3} (t + 2) (t - 3) d t

\int_{2}^{4} 2 x + 3 d x

What is the integral from pi/2 to 2pi of sin(x) ?
The integral from pi/2 to 2pi of sin(x) is -1