What is the integral from-1 to 2 of (x^2-3x-1) ?

The integral from-1 to 2 of (x^2-3x-1) is -9/2

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integral from-1 to 2 of (x^2-3x-1)

\int_{- 1}^{2} (x^{2} - 3 x - 1) d x

- \frac{9}{2}

Decimal

- 4.5

Solution steps

\int_{- 1}^{2} x^{2} - 3 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{2} d x - \int_{- 1}^{2} 3 x d x - \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} 3 x d x = \frac{9}{2}

\int_{- 1}^{2} 1 d x = 3

= 3 - \frac{9}{2} - 3

Simplify

= - \frac{9}{2}

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What is the integral from-1 to 2 of (x^2-3x-1) ?
The integral from-1 to 2 of (x^2-3x-1) is -9/2