What is the integral from x to 2x of e^{-t^2} ?

The integral from x to 2x of e^{-t^2} is (sqrt(pi))/2 \erf(2x)-(sqrt(pi))/2 \erf(x)

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integral from x to 2x of e^{-t^2}

\int_{x}^{2 x} e^{- t^{2}} d t

\frac{π}{2} erf (2 x) - \frac{π}{2} erf (x)

Solution steps

\int_{x}^{2 x} e^{- t^{2}} d t

Use the nonelementary integral:

\int e^{- t^{2}} d t = \frac{π}{2} erf (t)

= [\frac{π}{2} erf (t)]_{x}^{2 x}

Compute the boundaries:

\frac{π}{2} erf (2 x) - \frac{π}{2} erf (x)

= \frac{π}{2} erf (2 x) - \frac{π}{2} erf (x)

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\int_{0}^{x} x d x

\int_{0}^{2} (x^{2} + 3) d x

What is the integral from x to 2x of e^{-t^2} ?
The integral from x to 2x of e^{-t^2} is (sqrt(pi))/2 \erf(2x)-(sqrt(pi))/2 \erf(x)