What is the integral from-infinity to 0 of x/(x^2+1) ?

The integral from-infinity to 0 of x/(x^2+1) is diverges

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integral from-infinity to 0 of x/(x^2+1)

\int_{- \infty}^{0} \frac{x}{x ^{2} + 1} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{x}{x ^{2} + 1} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1 + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{x}{x ^{2} + 1} d x =

diverges

= diverges

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\int_{- 1}^{2} (x^{2} - x + 2) d x

\int_{0}^{\frac{π}{2}} sin^{2} (2 θ) d θ

\int_{0}^{\frac{1}{2}} x e^{3 x} d x

What is the integral from-infinity to 0 of x/(x^2+1) ?
The integral from-infinity to 0 of x/(x^2+1) is diverges