What is the integral from pi/6 to 2pi of cos(x) ?

The integral from pi/6 to 2pi of cos(x) is -1/2

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integral from pi/6 to 2pi of cos(x)

\int_{\frac{π}{6}}^{2 π} cos (x) d x

- \frac{1}{2}

Decimal

- 0.5

Solution steps

\int_{\frac{π}{6}}^{2 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{\frac{π}{6}}^{2 π}

Compute the boundaries:

- \frac{1}{2}

= - \frac{1}{2}

\int_{2}^{5} x - 1 d x

\int_{0}^{2 π} x cos (2 x) d x

\int_{0}^{1} x^{2} (1 - x)^{5} d x

\int_{0}^{2 π} t cos^{2} (t) d t

\int_{1}^{3} \frac{12 ( ln ( x ) ) ^{5}}{x} d x

What is the integral from pi/6 to 2pi of cos(x) ?
The integral from pi/6 to 2pi of cos(x) is -1/2