What is the integral from 0 to 3 of [x] ?

The integral from 0 to 3 of [x] is 9/2

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integral from 0 to 3 of [x]

\int_{0}^{3} [x] d x

\frac{9}{2}

Decimal

4.5

Solution steps

\int_{0}^{3} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3}

= [\frac{x ^{2}}{2}]_{0}^{3}

Compute the boundaries:

\frac{9}{2}

= \frac{9}{2}

\int_{0}^{\frac{π}{3}} (6 sec^{2} (x)) d x

\int_{1}^{3} x^{2} - x + 1 d x

\int_{0}^{1} \frac{1}{x ^{\frac{1}{4}}} d x

\int_{1}^{2} \frac{x ^{2}}{2} + \frac{x}{3} - \frac{1}{4} d x

\int_{- 2}^{- 1} \frac{1}{x x ^{2} + 1} d x

What is the integral from 0 to 3 of [x] ?
The integral from 0 to 3 of [x] is 9/2