What is the integral from 0 to 1 of 1/(\sqrt[5]{x)} ?

The integral from 0 to 1 of 1/(\sqrt[5]{x)} is 5/4

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integral from 0 to 1 of 1/(\sqrt[5]{x)}

\int_{0}^{1} \frac{1}{5 x} d x

\frac{5}{4}

Decimal

1.25

Solution steps

\int_{0}^{1} \frac{1}{5 x} d x

Apply the Power Rule

: [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{1}

= [\frac{5}{4} x^{\frac{4}{5}}]_{0}^{1}

Compute the boundaries:

\frac{5}{4}

= \frac{5}{4}

\int_{0}^{\frac{π}{2}} sin (2 n x) d x

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\int_{5}^{8} (x + 1) ln (2 x + 4) d x

\int_{2}^{5} (2 x + 1) d x

\int_{\frac{π}{2}}^{π} sin (x) - x d x

What is the integral from 0 to 1 of 1/(\sqrt[5]{x)} ?
The integral from 0 to 1 of 1/(\sqrt[5]{x)} is 5/4