What is the integral from 0 to 20pi of sin(x) ?

The integral from 0 to 20pi of sin(x) is 0

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integral from 0 to 20pi of sin(x)

\int_{0}^{20 π} sin (x) d x

0

Solution steps

\int_{0}^{20 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{20 π}

Compute the boundaries:

0

= 0

\int_{0}^{1} cos (\frac{π}{2} x) d x

\int_{0}^{1} (e^{x} + \frac{3}{2 - x}) d x

\int_{0}^{h} x d x

\int_{0}^{3} \frac{2 x}{1 + x ^{2}} d x

\int_{2}^{x} f (t) d t

What is the integral from 0 to 20pi of sin(x) ?
The integral from 0 to 20pi of sin(x) is 0