What is the integral from 1 to 2 of (15x^4-4x) ?

The integral from 1 to 2 of (15x^4-4x) is 87

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integral from 1 to 2 of (15x^4-4x)

\int_{1}^{2} (15 x^{4} - 4 x) d x

87

Solution steps

\int_{1}^{2} 15 x^{4} - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 15 x^{4} d x - \int_{1}^{2} 4 x d x

\int_{1}^{2} 15 x^{4} d x = 93

\int_{1}^{2} 4 x d x = 6

= 93 - 6

Simplify

= 87

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What is the integral from 1 to 2 of (15x^4-4x) ?
The integral from 1 to 2 of (15x^4-4x) is 87