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Popular >

integral from 0 to 4 of (x^2+4)

Solution

\int_{0}^{4} (x^{2} + 4) d x

Solution

\frac{112}{3}

+1

Decimal

37.33333 \dots

Solution steps

\int_{0}^{4} x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x + \int_{0}^{4} 4 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 d x = 16

= \frac{64}{3} + 16

Simplify

\frac{64}{3} + 16 : \frac{112}{3}

= \frac{112}{3}

Graph

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\int_{1}^{4} 2^{5 x} d x

integral from 0 to infinity of x^4

\int_{0}^{\infty} x^{4} d x

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\int_{2}^{\infty} - 9 x^{- 2} d x

integral from 1 to 6 of (5/x)

\int_{1}^{6} (\frac{5}{x}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x^2+4) ?
The integral from 0 to 4 of (x^2+4) is 112/3