What is the integral from a to b of sin(x) ?

The integral from a to b of sin(x) is -cos(b)+cos(a)

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integral from a to b of sin(x)

\int_{a}^{b} sin (x) d x

- cos (b) + cos (a)

Solution steps

\int_{a}^{b} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{a}^{b}

Compute the boundaries:

- cos (b) + cos (a)

= - cos (b) + cos (a)

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\int_{2}^{3} 9 - x^{2} d x

\int_{2}^{e} \frac{x ^{4} - 4 x}{x ^{2}} d x

\int_{2}^{3} 2 x x^{2} - 1 d x

What is the integral from a to b of sin(x) ?
The integral from a to b of sin(x) is -cos(b)+cos(a)