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Popular >

integral from-2 to 0 of |x+1|

Solution

\int_{- 2}^{0} ∣ x + 1 ∣ d x

Solution

1

Solution steps

\int_{- 2}^{0} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 2}^{- 1} - x - 1 d x + \int_{- 1}^{0} x + 1 d x

\int_{- 2}^{- 1} - x - 1 d x = \frac{1}{2}

\int_{- 1}^{0} x + 1 d x = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

\frac{1}{2} + \frac{1}{2} : 1

= 1

Graph

Popular Examples

integral from-7 to-3 of (-x^2-3x)

\int_{- 7}^{- 3} (- x^{2} - 3 x) d x

integral from 0 to x of 1/4

\int_{0}^{x} \frac{1}{4} d x

integral from-x to x^2 of (8x-10y+4)

\int_{- x}^{x^{2}} (8 x - 10 y + 4) d x

integral from-7 to-3 of-x^2-3x

\int_{- 7}^{- 3} - x^{2} - 3 x d x

integral from-5 to-4 of 2x+3

\int_{- 5}^{- 4} 2 x + 3 d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of |x+1| ?
The integral from-2 to 0 of |x+1| is 1