What is the integral from 1 to 6 of (cos(x))/x ?

The integral from 1 to 6 of (cos(x))/x is \Ci(6)-\Ci(1)

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integral from 1 to 6 of (cos(x))/x

\int_{1}^{6} \frac{cos ( x )}{x} d x

Ci (6) - Ci (1)

Decimal

- 0.40546 \dots

Solution steps

\int_{1}^{6} \frac{cos ( x )}{x} d x

Use the nonelementary integral:

\int \frac{cos ( x )}{x} d x = Ci (x)

= [Ci (x)]_{1}^{6}

Compute the boundaries:

Ci (6) - Ci (1)

= Ci (6) - Ci (1)

\int_{0}^{2} 1 + x d x

\int_{0}^{3} (x - 2) d x

\int_{1}^{2} \frac{e ^{\frac{1}{2}}}{x ^{2}} d x

\int_{1}^{2 e} ln (x) d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} x^{2} sin (x) d x

What is the integral from 1 to 6 of (cos(x))/x ?
The integral from 1 to 6 of (cos(x))/x is \Ci(6)-\Ci(1)