What is the integral from 0 to e^{-z^4 of}z ?

The integral from 0 to e^{-z^4 of}z is 1/2 e^{-2z^4}

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integral from 0 to e^{-z^4 of}z

\int_{0}^{e^{- z^{4}}} z d z

\frac{1}{2} e^{- 2 z^{4}}

Solution steps

\int_{0}^{e^{- z^{4}}} z d z

Apply the Power Rule

: [\frac{z ^{2}}{2}]_{0}^{e^{- z^{4}}}

= [\frac{z ^{2}}{2}]_{0}^{e^{- z^{4}}}

Compute the boundaries:

\frac{1}{2} e^{- 2 z^{4}}

= \frac{1}{2} e^{- 2 z^{4}}

\int_{0}^{x^{2}} t^{\frac{3}{2}} d t

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\int_{1}^{2} x ln (2 x) d x

\int_{0}^{π} - sin^{2} (t) d t

What is the integral from 0 to e^{-z^4 of}z ?
The integral from 0 to e^{-z^4 of}z is 1/2 e^{-2z^4}