What is the integral from 0 to 1-x-y of 1 ?

The integral from 0 to 1-x-y of 1 is 1-x-y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1-x-y of 1

\int_{0}^{1 - x - y} 1 d z

1 - x - y

Solution steps

\int_{0}^{1 - x - y} 1 d z

Integral of a constant:

\int a d x = a x

= [1 \cdot z]_{0}^{1 - x - y}

Simplify

= [z]_{0}^{1 - x - y}

Compute the boundaries:

1 - x - y

= 1 - x - y

\int_{- 3}^{- 1} x^{2} d x

\int_{- \frac{π}{2}}^{π} 11 cos (x) d x

\int_{0}^{2} \frac{1}{4 + t ^{2}} d t

\int_{4}^{8} 1

\int_{0}^{1} \frac{x}{8} d x

What is the integral from 0 to 1-x-y of 1 ?
The integral from 0 to 1-x-y of 1 is 1-x-y