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Popular >

integral from-1 to 0 of 1+x

Solution

\int_{- 1}^{0} 1 + x d x

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{- 1}^{0} 1 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 1 d x + \int_{- 1}^{0} x d x

\int_{- 1}^{0} 1 d x = 1

\int_{- 1}^{0} x d x = - \frac{1}{2}

= 1 - \frac{1}{2}

Simplify

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2}

Graph

Popular Examples

integral from 1 to 2 of (5x)

\int_{1}^{2} (5 x) d x

integral from 0 to 2 of sin((pix)/2)

\int_{0}^{2} sin (\frac{π x}{2}) d x

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\int_{0}^{3} - t e^{- t^{2}} d t

integral from 0 to log_{3 of (8)}3^x

\int_{0}^{l o g_{3} (8)} 3^{x} d x

integral from 0 to a of x^3f(x^2)

\int_{0}^{a} x^{3} f (x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of 1+x ?
The integral from-1 to 0 of 1+x is 1/2