What is the integral from-2 to 2 of xcos(x^2+1) ?

The integral from-2 to 2 of xcos(x^2+1) is 0

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integral from-2 to 2 of xcos(x^2+1)

\int_{- 2}^{2} x cos (x^{2} + 1) d x

0

Solution steps

\int_{- 2}^{2} x cos (x^{2} + 1) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x cos (x^{2} + 1) :

Odd

= 0

\int_{0}^{\frac{π}{4}} (3 cos (2 x))^{2} d x

\int_{- \frac{π}{4}}^{\frac{π}{4}} cos^{7} (2 x) d x

\int_{0}^{9} (4 t^{2} + t^{\frac{3}{2}}) d t

\int_{- 1}^{2} (x^{2} - 5 x + 1) d x

\int_{0}^{4} x^{2} e^{\frac{x}{2}} d x

What is the integral from-2 to 2 of xcos(x^2+1) ?
The integral from-2 to 2 of xcos(x^2+1) is 0