What is the integral from-1 to 2 of x-(x^2-2) ?

The integral from-1 to 2 of x-(x^2-2) is 9/2

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integral from-1 to 2 of x-(x^2-2)

\int_{- 1}^{2} x - (x^{2} - 2) d x

\frac{9}{2}

Decimal

4.5

Solution steps

\int_{- 1}^{2} x - (x^{2} - 2) d x

Simplify

= \int_{- 1}^{2} x - x^{2} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x - \int_{- 1}^{2} x^{2} d x + \int_{- 1}^{2} 2 d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} 2 d x = 6

= \frac{3}{2} - 3 + 6

Simplify

\frac{3}{2} - 3 + 6 : \frac{9}{2}

= \frac{9}{2}

\int_{0}^{x} e^{t^{3}} d t

\int_{0}^{1} \frac{t}{t + 1} d t

\int_{0}^{\frac{1}{3}} - 3 x^{2} + x d x

\int_{0}^{1} y^{2} y^{3} + 1 d y

\int_{0}^{2} 16 - x^{2} d x

What is the integral from-1 to 2 of x-(x^2-2) ?
The integral from-1 to 2 of x-(x^2-2) is 9/2