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Popular >

integral from 1 to 5 of |x-2|

Solution

\int_{1}^{5} ∣ x - 2 ∣ d x

Solution

5

Solution steps

\int_{1}^{5} ∣ x - 2 ∣ d x

Eliminate Absolutes

= \int_{1}^{2} - x + 2 d x + \int_{2}^{5} x - 2 d x

\int_{1}^{2} - x + 2 d x = \frac{1}{2}

\int_{2}^{5} x - 2 d x = \frac{9}{2}

= \frac{1}{2} + \frac{9}{2}

Simplify

\frac{1}{2} + \frac{9}{2} : 5

= 5

Graph

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\int_{2}^{3} 8 x d x

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\int_{0}^{2 π} - 50 sin^{2} (t) d t

integral from 4x to-5 of sin(t^2)

\int_{4 x}^{- 5} sin (t^{2}) d t

Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of |x-2| ?
The integral from 1 to 5 of |x-2| is 5