What is the integral from 0 to pi/6 of 16cos(x) ?

The integral from 0 to pi/6 of 16cos(x) is 8

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integral from 0 to pi/6 of 16cos(x)

\int_{0}^{\frac{π}{6}} 16 cos (x) d x

8

Solution steps

\int_{0}^{\frac{π}{6}} 16 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 16 \cdot \int_{0}^{\frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 16 [sin (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2}

= 16 \cdot \frac{1}{2}

Simplify

= 8

\int_{1}^{2} ln (2 x) d x

\int_{- l}^{0} (x + l) d x

\int_{0}^{4} \frac{1}{1 + t} d t

\int_{0}^{2} - 2 x^{3} + 8 x d x

\int_{0}^{\frac{y}{3}} \frac{y ^{2} - 9 x ^{2}}{2} d x

What is the integral from 0 to pi/6 of 16cos(x) ?
The integral from 0 to pi/6 of 16cos(x) is 8