What is the integral from-2 to 0 of \sqrt[3]{x} ?

The integral from-2 to 0 of \sqrt[3]{x} is (3\sqrt[3]{-1})/(2^{2/3)}

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integral from-2 to 0 of \sqrt[3]{x}

\int_{- 2}^{0} 3 x d x

\frac{3 3 - 1}{2 ^{\frac{2}{3}}}

Solution steps

\int_{- 2}^{0} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{0}

= [\frac{3}{4} x^{\frac{4}{3}}]_{- 2}^{0}

Compute the boundaries:

\frac{3 3 - 1}{2 ^{\frac{2}{3}}}

= \frac{3 3 - 1}{2 ^{\frac{2}{3}}}

\int_{0}^{x^{2}} x d x

\int_{1}^{2} x ln (1 + x^{2}) d x

\int_{- 3}^{0} x^{3} + 2 x^{2} - 3 x d x

\int_{1}^{7} x d x

\int_{0}^{π} tan (\frac{x}{4}) d x

What is the integral from-2 to 0 of \sqrt[3]{x} ?
The integral from-2 to 0 of \sqrt[3]{x} is (3\sqrt[3]{-1})/(2^{2/3)}