What is the integral from 0 to 3 of 7^x ?

The integral from 0 to 3 of 7^x is (342)/(ln(7))

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integral from 0 to 3 of 7^x

\int_{0}^{3} 7^{x} d x

\frac{342}{ln ( 7 )}

Decimal

175.75323 \dots

Solution steps

\int_{0}^{3} 7^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{7 ^{x}}{ln ( 7 )}]_{0}^{3}

Compute the boundaries:

\frac{342}{ln ( 7 )}

= \frac{342}{ln ( 7 )}

\int_{2}^{3} (x^{2} + 2) d x

\int_{2}^{3} \frac{9}{( 3 x + 2 ) ^{4}} d x

\int_{- 1}^{1} 2 - x^{2} - x^{2} d x

\int_{0}^{2 π} 1 - cos (2 x) d x

\int_{0}^{1} (x^{2} - 2 x + 7) d x

What is the integral from 0 to 3 of 7^x ?
The integral from 0 to 3 of 7^x is (342)/(ln(7))