What is the integral from 0 to x^2 of sin(x) ?

The integral from 0 to x^2 of sin(x) is -cos(x^2)+1

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integral from 0 to x^2 of sin(x)

\int_{0}^{x^{2}} sin (x) d x

- cos (x^{2}) + 1

Solution steps

\int_{0}^{x^{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{x^{2}}

Compute the boundaries:

- cos (x^{2}) + 1

= - cos (x^{2}) + 1

\int_{0}^{π} cos (x + y + z) d x

\int_{0}^{2} (\frac{x}{2}) d x

\int_{0}^{1} (5 x^{e} + 7 e^{x}) d x

\int_{0}^{2} (3 x^{2} - x + 1) d x

\int_{0}^{4} (x - 3 x) d x

What is the integral from 0 to x^2 of sin(x) ?
The integral from 0 to x^2 of sin(x) is -cos(x^2)+1