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Popular >

integral from-2 to 0 of 4-x^2

Solution

\int_{- 2}^{0} 4 - x^{2} d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{- 2}^{0} 4 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{0} 4 d x - \int_{- 2}^{0} x^{2} d x

\int_{- 2}^{0} 4 d x = 8

\int_{- 2}^{0} x^{2} d x = \frac{8}{3}

= 8 - \frac{8}{3}

Simplify

8 - \frac{8}{3} : \frac{16}{3}

= \frac{16}{3}

Graph

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\int_{0}^{2 x} cos (x) d x

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\int_{0}^{x} t e^{- t} d t

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\int_{0}^{1} 12 x^{2} d x

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\int_{0}^{5} \frac{8}{7 x + 6} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 0 of 4-x^2 ?
The integral from-2 to 0 of 4-x^2 is 16/3