What is the integral from 0 to 1 of cos(t) ?

The integral from 0 to 1 of cos(t) is sin(1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of cos(t)

\int_{0}^{1} cos (t) d t

sin (1)

Decimal

0.84147 \dots

Solution steps

\int_{0}^{1} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{0}^{1}

Compute the boundaries:

sin (1)

= sin (1)

\int_{0}^{3} ∣ 5 x - 9 ∣ d x

\int_{0}^{a} x^{- \frac{4}{3}} d x

\int_{- 1}^{2} x x^{2} - 1 d x

\int_{0}^{\frac{7}{9}} \frac{1}{81 x ^{2} + 49} d x

\int_{x}^{5} cos (e^{t}) d t

What is the integral from 0 to 1 of cos(t) ?
The integral from 0 to 1 of cos(t) is sin(1)