What is the integral from 1 to infinity of 4x^{-5} ?

The integral from 1 to infinity of 4x^{-5} is 1

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integral from 1 to infinity of 4x^{-5}

\int_{1}^{\infty} 4 x^{- 5} d x

1

Solution steps

\int_{1}^{\infty} 4 x^{- 5} d x

Compute the indefinite integral:

\int 4 x^{- 5} d x = - \frac{1}{x ^{4}} + C

Compute the boundaries:

\int_{1}^{\infty} 4 x^{- 5} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

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What is the integral from 1 to infinity of 4x^{-5} ?
The integral from 1 to infinity of 4x^{-5} is 1