What is the integral from 1 to 4 of x^2+sqrt(x) ?

The integral from 1 to 4 of x^2+sqrt(x) is 77/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of x^2+sqrt(x)

\int_{1}^{4} x^{2} + x d x

\frac{77}{3}

Decimal

25.66666 \dots

Solution steps

\int_{1}^{4} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} x d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} x d x = \frac{14}{3}

= 21 + \frac{14}{3}

Simplify

21 + \frac{14}{3} : \frac{77}{3}

= \frac{77}{3}

\int_{1}^{3} arctan (x) d x

\int_{0}^{4} (8 x + x) d x

\int_{- \infty}^{0} 1 d x

\int_{0}^{2} 1 + 2 x^{2} d x

\int_{0}^{2} (- t^{2} + 3 t - 2) d t

What is the integral from 1 to 4 of x^2+sqrt(x) ?
The integral from 1 to 4 of x^2+sqrt(x) is 77/3