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Popular >

integral from-1 to 0 of (1+x)

Solution

\int_{- 1}^{0} (1 + x) d x

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{- 1}^{0} 1 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 1 d x + \int_{- 1}^{0} x d x

\int_{- 1}^{0} 1 d x = 1

\int_{- 1}^{0} x d x = - \frac{1}{2}

= 1 - \frac{1}{2}

Simplify

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2}

Graph

Popular Examples

integral from-1 to 4 of (2x+1)

\int_{- 1}^{4} (2 x + 1) d x

integral from-pi to pi of x^2sin^3(x)

\int_{- π}^{π} x^{2} sin^{3} (x) d x

integral from-2 to 0 of sqrt(x^3)

\int_{- 2}^{0} x^{3} d x

integral from 2 to 7 of tsqrt(t+2)

\int_{2}^{7} t t + 2 d t

integral from-1 to 2 of (3x^2-2x+1)

\int_{- 1}^{2} (3 x^{2} - 2 x + 1) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (1+x) ?
The integral from-1 to 0 of (1+x) is 1/2