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Popular >

integral from 1 to 2 of (1-x)

Solution

\int_{1}^{2} (1 - x) d x

Solution

- \frac{1}{2}

+1

Decimal

- 0.5

Solution steps

\int_{1}^{2} 1 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d x - \int_{1}^{2} x d x

\int_{1}^{2} 1 d x = 1

\int_{1}^{2} x d x = \frac{3}{2}

= 1 - \frac{3}{2}

Simplify

1 - \frac{3}{2} : - \frac{1}{2}

= - \frac{1}{2}

Graph

Popular Examples

integral from 0 to 1 of 8/(t^2+1)

\int_{0}^{1} \frac{8}{t ^{2} + 1} d t

integral from 5 to x^2 of 1/(t^5)

\int_{5}^{x^{2}} \frac{1}{t ^{5}} d t

integral from 2 to-1 of (x^2-x-2)

\int_{2}^{- 1} (x^{2} - x - 2) d x

integral from 1 to 2 of x/((x^2+4)^3)

\int_{1}^{2} \frac{x}{( x ^{2} + 4 ) ^{3}} d x

integral from-1 to 1 of cos(pi/3 x)

\int_{- 1}^{1} cos (\frac{π}{3} x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (1-x) ?
The integral from 1 to 2 of (1-x) is -1/2