What is the integral from 0 to 4 of 3/16 sqrt(x) ?

The integral from 0 to 4 of 3/16 sqrt(x) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of 3/16 sqrt(x)

\int_{0}^{4} \frac{3}{16} x d x

1

Solution steps

\int_{0}^{4} \frac{3}{16} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{16} \cdot \int_{0}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

= \frac{3}{16} [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{3}{16} \cdot \frac{16}{3}

Simplify

= 1

\int_{1}^{2} \frac{1}{2 x} d x

\int_{- 1}^{1} (x^{4} - x^{8}) d x

\int_{0}^{4.4} 3 3 x + 4 d x

\int_{- 3}^{1} (3 - x^{2} - 2 x) d x

\int_{0}^{\frac{π}{4}} 6 x^{2} + tan (x) d x

What is the integral from 0 to 4 of 3/16 sqrt(x) ?
The integral from 0 to 4 of 3/16 sqrt(x) is 1