What is the integral from 1 to infinity of 1/(2x) ?

The integral from 1 to infinity of 1/(2x) is diverges

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integral from 1 to infinity of 1/(2x)

\int_{1}^{\infty} \frac{1}{2 x} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{2 x} d x

Compute the indefinite integral:

\int \frac{1}{2 x} d x = \frac{1}{2} ln ∣ x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{2 x} d x =

diverges

= diverges

\int_{1}^{3} (x - 1)^{2} d x

\int_{0}^{2} 3 x (2 - x) d x

\int_{0}^{1} 10 x d x

\int_{0}^{3} r^{3} d r

\int_{0}^{1} \frac{x}{3 x + 1} d x

What is the integral from 1 to infinity of 1/(2x) ?
The integral from 1 to infinity of 1/(2x) is diverges