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Popular >

integral from 1 to 2 of (x^2+x)

Solution

\int_{1}^{2} (x^{2} + x) d x

Solution

\frac{23}{6}

+1

Decimal

3.83333 \dots

Solution steps

\int_{1}^{2} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x + \int_{1}^{2} x d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} x d x = \frac{3}{2}

= \frac{7}{3} + \frac{3}{2}

Simplify

\frac{7}{3} + \frac{3}{2} : \frac{23}{6}

= \frac{23}{6}

Graph

Popular Examples

integral from 0 to 5 of 15e^{3x}

\int_{0}^{5} 15 e^{3 x} d x

integral from 0 to 1 of 2-2x^2

\int_{0}^{1} 2 - 2 x^{2} d x

integral from pi/4 to pi/2 of sin(t)

\int_{\frac{π}{4}}^{\frac{π}{2}} sin (t) d t

integral from 0 to pi/2 of 1-cos(x)

\int_{0}^{\frac{π}{2}} 1 - cos (x) d x

integral from 0 to 1 of 4x^3ln(x)

\int_{0}^{1} 4 x^{3} ln (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x^2+x) ?
The integral from 1 to 2 of (x^2+x) is 23/6