What is the integral from-infinity to 2 of 6e^{3x} ?

The integral from-infinity to 2 of 6e^{3x} is 2e^6

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integral from-infinity to 2 of 6e^{3x}

\int_{- \infty}^{2} 6 e^{3 x} d x

2 e^{6}

Decimal

806.85758 \dots

Solution steps

\int_{- \infty}^{2} 6 e^{3 x} d x

Compute the indefinite integral:

\int 6 e^{3 x} d x = 2 e^{3 x} + C

Compute the boundaries:

\int_{- \infty}^{2} 6 e^{3 x} d x = 2 e^{6} - 0

= 2 e^{6} - 0

Simplify

= 2 e^{6}

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What is the integral from-infinity to 2 of 6e^{3x} ?
The integral from-infinity to 2 of 6e^{3x} is 2e^6