What is the integral from-3 to 2 of bx-ax^2 ?

The integral from-3 to 2 of bx-ax^2 is -(5b)/2-(35a)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 2 of bx-ax^2

\int_{- 3}^{2} b x - a x^{2} d x

- \frac{5 b}{2} - \frac{35 a}{3}

Solution steps

\int_{- 3}^{2} b x - a x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{2} b x d x - \int_{- 3}^{2} a x^{2} d x

\int_{- 3}^{2} b x d x = - \frac{5 b}{2}

\int_{- 3}^{2} a x^{2} d x = \frac{35 a}{3}

= - \frac{5 b}{2} - \frac{35 a}{3}

\int_{0}^{\infty} x^{2} e^{\frac{- x}{2}} d x

\int_{0}^{1} e^{- ik x} d x

\int_{0}^{0.75} 2 - 2 x d x

\int_{- 1}^{1} (x^{4} - x^{6}) d x

\int_{0}^{3} 5^{x} d x

What is the integral from-3 to 2 of bx-ax^2 ?
The integral from-3 to 2 of bx-ax^2 is -(5b)/2-(35a)/3