What is the integral from 4 to 9 of x^{-3/2} ?

The integral from 4 to 9 of x^{-3/2} is 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 4 to 9 of x^{-3/2}

\int_{4}^{9} x^{- \frac{3}{2}} d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{4}^{9} x^{- \frac{3}{2}} d x

Apply the Power Rule

: [- \frac{2}{x ^{\frac{1}{2}}}]_{4}^{9}

= [- \frac{2}{x ^{\frac{1}{2}}}]_{4}^{9}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\int_{- 3}^{3} π (9 - x^{2}) d x

\int_{1}^{5} (3 x^{2} + 5 x) d x

\int_{- 1}^{2} [(x + 2) - x^{2}] d x

\int_{0}^{l n (A)} 4 e^{2 x} d x

\int_{1}^{5} (2 x^{2} - 12 x + 10) d x

What is the integral from 4 to 9 of x^{-3/2} ?
The integral from 4 to 9 of x^{-3/2} is 1/3