What is the integral from-1 to 1 of sqrt(t^3) ?

The integral from-1 to 1 of sqrt(t^3) is 2/5-i 2/5

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integral from-1 to 1 of sqrt(t^3)

\int_{- 1}^{1} t^{3} d t

\frac{2}{5} - i \frac{2}{5}

Solution steps

\int_{- 1}^{1} t^{3} d t

t^{3} = t^{\frac{3}{2}},

assuming

t \geq 0

= \int_{- 1}^{1} t^{\frac{3}{2}} d t

Apply the Power Rule

: [\frac{2}{5} t^{\frac{5}{2}}]_{- 1}^{1}

= [\frac{2}{5} t^{\frac{5}{2}}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{5} - i \frac{2}{5}

= \frac{2}{5} - i \frac{2}{5}

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What is the integral from-1 to 1 of sqrt(t^3) ?
The integral from-1 to 1 of sqrt(t^3) is 2/5-i 2/5