What is the integral from 1 to infinity of 7x^{-8} ?

The integral from 1 to infinity of 7x^{-8} is 1

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integral from 1 to infinity of 7x^{-8}

\int_{1}^{\infty} 7 x^{- 8} d x

1

Solution steps

\int_{1}^{\infty} 7 x^{- 8} d x

Compute the indefinite integral:

\int 7 x^{- 8} d x = - \frac{1}{x ^{7}} + C

Compute the boundaries:

\int_{1}^{\infty} 7 x^{- 8} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

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\int_{- 1}^{1} 7 d x

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What is the integral from 1 to infinity of 7x^{-8} ?
The integral from 1 to infinity of 7x^{-8} is 1