What is the integral from 0 to 4 of-x ?

The integral from 0 to 4 of-x is -8

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integral from 0 to 4 of-x

\int_{0}^{4} - x d x

- 8

Solution steps

\int_{0}^{4} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{4}

= - [\frac{x ^{2}}{2}]_{0}^{4}

Compute the boundaries:

8

= - 8

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