What is the integral from 2 to-2 of x^2 ?

The integral from 2 to-2 of x^2 is -16/3

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integral from 2 to-2 of x^2

\int_{2}^{- 2} x^{2} d x

- \frac{16}{3}

Decimal

- 5.33333 \dots

Solution steps

\int_{2}^{- 2} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 2}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{2}

= - [\frac{x ^{3}}{3}]_{- 2}^{2}

Compute the boundaries:

\frac{16}{3}

= - \frac{16}{3}

\int_{- 2}^{2} x^{3} + 3 x^{2} - 2 x + 4 d x

\int_{2}^{6} (x + 1) (x^{2} + 2 x)^{2} d x

\int_{1}^{11} 1 d x

\int_{0}^{8} 8 y - y^{2} d y

\int_{- 4}^{0} x d x

What is the integral from 2 to-2 of x^2 ?
The integral from 2 to-2 of x^2 is -16/3