What is the integral from 0 to 1 of 3\sqrt[3]{x} ?

The integral from 0 to 1 of 3\sqrt[3]{x} is 9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 3\sqrt[3]{x}

\int_{0}^{1} 3 3 x d x

\frac{9}{4}

Decimal

2.25

Solution steps

\int_{0}^{1} 3 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{1}

= 3 [\frac{3}{4} x^{\frac{4}{3}}]_{0}^{1}

Compute the boundaries:

\frac{3}{4}

= 3 \cdot \frac{3}{4}

Simplify

= \frac{9}{4}

\int_{1}^{2} 2 y d y

\int_{- 2}^{3} (2 x^{4} + 4 x^{3} - x + 3) d x

\int_{0}^{6} (36 - x^{2}) d x

\int_{x^{3}}^{x} e^{\frac{y}{x}} d y

\int_{0}^{x} \frac{1}{( 1 - x ) ^{2.37}} d x

What is the integral from 0 to 1 of 3\sqrt[3]{x} ?
The integral from 0 to 1 of 3\sqrt[3]{x} is 9/4