What is the integral from 2 to x of u^4 ?

The integral from 2 to x of u^4 is (x^5-32)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to x of u^4

\int_{2}^{x} u^{4} d u

\frac{x ^{5} - 32}{5}

Solution steps

\int_{2}^{x} u^{4} d u

Apply the Power Rule

: [\frac{u ^{5}}{5}]_{2}^{x}

= [\frac{u ^{5}}{5}]_{2}^{x}

Compute the boundaries:

\frac{x ^{5}}{5} - \frac{32}{5}

= \frac{x ^{5}}{5} - \frac{32}{5}

Simplify

= \frac{x ^{5} - 32}{5}

\int_{0}^{1} e^{6 x - 5} d x

\int_{0}^{10} 3 x d x

\int_{- 2}^{2} t^{3} (4 + t^{4})^{3} d t

\int_{2}^{5} (x^{2} - 7 x + 10) d x

\int_{2}^{3} (2 x - 3)^{4} d x

What is the integral from 2 to x of u^4 ?
The integral from 2 to x of u^4 is (x^5-32)/5