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Popular >

integral from-1 to 1 of (x+y+1)

Solution

\int_{- 1}^{1} (x + y + 1) d x

Solution

2 y + 2

Solution steps

\int_{- 1}^{1} x + y + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} y d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} y d x = 2 y

\int_{- 1}^{1} x d x = 0

= 2 + 2 y + 0

Simplify

= 2 y + 2

Popular Examples

integral from 0 to 3 of 200+10t+1/3 t^2

\int_{0}^{3} 200 + 10 t + \frac{1}{3} t^{2} d t

integral from 0 to 1 of 7x^2

\int_{0}^{1} 7 x^{2} d x

integral from 0 to pi/n of xsin(nx)

\int_{0}^{\frac{π}{n}} x sin (n x) d x

integral from 1 to cos(x) of 3t^2

\int_{1}^{c o s (x)} 3 t^{2} d t

integral from 0 to 2 of cos(2x)

\int_{0}^{2} cos (2 x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (x+y+1) ?
The integral from-1 to 1 of (x+y+1) is 2y+2