What is the integral from 0 to log_{7 of (8)}7^x ?

The integral from 0 to log_{7 of (8)}7^x is 7/(ln(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to log_{7 of (8)}7^x

\int_{0}^{l o g_{7} (8)} 7^{x} d x

\frac{7}{ln ( 7 )}

Decimal

3.59728 \dots

Solution steps

\int_{0}^{l o g_{7} (8)} 7^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{7 ^{x}}{ln ( 7 )}]_{0}^{l o g_{7} (8)}

Simplify

lo g_{7} (8) : 3 lo g_{7} (2)

= [\frac{7 ^{x}}{ln ( 7 )}]_{0}^{3 l o g_{7} (2)}

Compute the boundaries:

\frac{7}{ln ( 7 )}

= \frac{7}{ln ( 7 )}

\int_{0}^{1} \frac{x}{( x + 1 ) ^{8}} d x

\int_{3}^{9} \frac{1}{x ( ln ( x ) ) ^{9}} d x

\int_{0}^{2} sin (\frac{π}{2} x) d x

\int_{- 1}^{1} (x + y + z) d x

\int_{1}^{5} (\frac{4}{x} - e^{- x}) d x

What is the integral from 0 to log_{7 of (8)}7^x ?
The integral from 0 to log_{7 of (8)}7^x is 7/(ln(7))